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1856 United States presidential election in New Jersey

1856 United States presidential election in New Jersey

← 1852 November 4, 1856 1860 →
  Hon. James Buchanan - NARA - 528318-crop.jpg John Charles Fremont crop.jpg Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan John C. Frémont Millard Fillmore
Party Democratic Republican Know Nothing
Home state Pennsylvania California New York
Running mate John C. Breckinridge William L. Dayton Andrew Jackson Donelson
Electoral vote 7 0 0
Popular vote 46,943 28,338 24,115
Percentage 47.23% 28.51% 24.26%

President before election

Franklin Pierce

Elected President

James Buchanan

The 1856 United States presidential election in New Jersey took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 35 representatives, or electors to the Electoral College, who voted for president and vice president.

New Jersey voted for the Democratic candidate, James Buchanan, over Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore. Buchanan won the state by a margin of 13.43%.


1856 United States presidential election in New Jersey[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 46,943 47.23% 7 100.00%
Republican John C. Frémont of California William L. Dayton of New Jersey 28,338 28.51% 0 0.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 24,115 24.26% 0 0.00%
Total 99,396 100.00% 7 100.00%


  1. ^ "1856 Presidential General Election Results - New Jersey".